SUNDANESE SIGN PANGWISAD·U+1B82

Character Information

Code Point
U+1B82
HEX
1B82
Unicode Plane
Basic Multilingual Plane
Category
Spacing Mark

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 AE 82
11100001 10101110 10000010
UTF16 (big Endian)
1B 82
00011011 10000010
UTF16 (little Endian)
82 1B
10000010 00011011
UTF32 (big Endian)
00 00 1B 82
00000000 00000000 00011011 10000010
UTF32 (little Endian)
82 1B 00 00
10000010 00011011 00000000 00000000
HTML Entity
ᮂ
URI Encoded
%E1%AE%82

Description

U+1B82, the Sundanese Sign Pangwisad, is a typographical character with a crucial role in digital text representing the Sundanese language. It belongs to the Unicode standard, a system that allows for global communication by assigning unique codes to characters from various languages. The Sundanese Sign Pangwisad holds cultural significance as it is specifically used in the written form of the Sundanese language, spoken predominantly in West Java, Indonesia. Its primary usage lies in marking the juncture between two words or phrases, serving a grammatical function similar to that of a hyphen or space in other languages. The accurate use of this character is essential for preserving the integrity of written Sundanese and maintaining its linguistic identity in digital contexts.

How to type the symbol on Windows

Hold Alt and type 7042 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1B82. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1B82 to binary: 00011011 10000010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10101110 10000010