SUNDANESE SIGN PANGLAYAR·U+1B81

Character Information

Code Point
U+1B81
HEX
1B81
Unicode Plane
Basic Multilingual Plane
Category
Nonspacing Mark

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 AE 81
11100001 10101110 10000001
UTF16 (big Endian)
1B 81
00011011 10000001
UTF16 (little Endian)
81 1B
10000001 00011011
UTF32 (big Endian)
00 00 1B 81
00000000 00000000 00011011 10000001
UTF32 (little Endian)
81 1B 00 00
10000001 00011011 00000000 00000000
HTML Entity
ᮁ
URI Encoded
%E1%AE%81

Description

U+1B81, also known as the Sundanese Sign Panglayar, is a unique Unicode character primarily used within the Sundanese language, which is spoken predominantly in West Java, Indonesia. This character plays an essential role in digital text by serving as a crucial component of the Sundanese writing system, specifically in conveying the linguistic nuances and phonological features that are specific to this language. The Panglayar sign represents a specific consonant or a combination of sounds within the Sundanese script, demonstrating its importance in accurately transcribing and translating Sundanese text. As part of Unicode, U+1B81 allows for greater interoperability and accessibility among digital platforms, fostering communication and preservation of this rich cultural heritage.

How to type the symbol on Windows

Hold Alt and type 7041 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1B81. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1B81 to binary: 00011011 10000001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10101110 10000001