EQUIVALENT WITH FOUR DOTS ABOVE·U+2A78

Character Information

Code Point
U+2A78
HEX
2A78
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 A9 B8
11100010 10101001 10111000
UTF16 (big Endian)
2A 78
00101010 01111000
UTF16 (little Endian)
78 2A
01111000 00101010
UTF32 (big Endian)
00 00 2A 78
00000000 00000000 00101010 01111000
UTF32 (little Endian)
78 2A 00 00
01111000 00101010 00000000 00000000
HTML Entity
⩸
URI Encoded
%E2%A9%B8

Description

U+2A78 is a typographical character known as "Equivalent with Four Dots Above" in Unicode. It is commonly used in mathematical notation to indicate the equivalence of two expressions or values. The character is particularly prevalent in fields such as computer science, mathematics, and engineering where precision and clarity are essential. While this character may not have a direct equivalent in traditional written languages, its use in digital text has become increasingly important for maintaining consistency and accuracy across various software applications and systems. The Unicode standard ensures that U+2A78 is displayed correctly across different platforms and devices, allowing for smooth communication of complex mathematical concepts and relationships.

How to type the symbol on Windows

Hold Alt and type 10872 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2A78. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2A78 to binary: 00101010 01111000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101001 10111000