LESS-THAN WITH CIRCLE INSIDE·U+2A79

Character Information

Code Point
U+2A79
HEX
2A79
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 A9 B9
11100010 10101001 10111001
UTF16 (big Endian)
2A 79
00101010 01111001
UTF16 (little Endian)
79 2A
01111001 00101010
UTF32 (big Endian)
00 00 2A 79
00000000 00000000 00101010 01111001
UTF32 (little Endian)
79 2A 00 00
01111001 00101010 00000000 00000000
HTML Entity
⩹
URI Encoded
%E2%A9%B9

Description

U+2A79 is a Unicode character, known as LESS-THAN WITH CIRCLE INSIDE. This symbol is typically used in digital text for representing an inequality involving fractions or decimals in mathematical expressions. It is particularly useful in various fields of mathematics and science where the comparison of fractions or decimals is required. In its design, this character features a less-than sign enclosed within a circle, which can be seen as both a visual and functional representation of the inequality concept. The inclusion of the circle adds an element of sophistication to the symbol, enhancing its readability in digital text. There aren't any notable cultural, linguistic, or technical contexts associated with U+2A79, but it serves as a crucial component for accurate and clear mathematical communication.

How to type the symbol on Windows

Hold Alt and type 10873 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2A79. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2A79 to binary: 00101010 01111001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101001 10111001