GREATER-THAN WITH QUESTION MARK ABOVE·U+2A7C

Character Information

Code Point
U+2A7C
HEX
2A7C
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 A9 BC
11100010 10101001 10111100
UTF16 (big Endian)
2A 7C
00101010 01111100
UTF16 (little Endian)
7C 2A
01111100 00101010
UTF32 (big Endian)
00 00 2A 7C
00000000 00000000 00101010 01111100
UTF32 (little Endian)
7C 2A 00 00
01111100 00101010 00000000 00000000
HTML Entity
⩼
URI Encoded
%E2%A9%BC

Description

The Unicode character U+2A7C, also known as "GREATER-THAN WITH QUESTION MARK ABOVE," is a rarely used typographical symbol that combines the greater-than sign (>) with a question mark (?). Its primary role in digital text is to indicate an uncertain or tentative result in comparisons or evaluations. Although not widely employed, this character can be valuable in specific contexts such as programming, mathematics, and technical writing where clear expression of uncertainty or partial truth is essential. The GREATER-THAN WITH QUESTION MARK ABOVE can also be used in creative typography to add a touch of whimsy or humor to text. Despite its limited usage, this Unicode character offers a unique option for representing doubt or ambiguity in digital communications.

How to type the symbol on Windows

Hold Alt and type 10876 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2A7C. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2A7C to binary: 00101010 01111100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101001 10111100