LESS-THAN WITH QUESTION MARK ABOVE·U+2A7B

Character Information

Code Point
U+2A7B
HEX
2A7B
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 A9 BB
11100010 10101001 10111011
UTF16 (big Endian)
2A 7B
00101010 01111011
UTF16 (little Endian)
7B 2A
01111011 00101010
UTF32 (big Endian)
00 00 2A 7B
00000000 00000000 00101010 01111011
UTF32 (little Endian)
7B 2A 00 00
01111011 00101010 00000000 00000000
HTML Entity
⩻
URI Encoded
%E2%A9%BB

Description

The Unicode character U+2A7B is known as the "LESS-THAN WITH QUESTION MARK ABOVE" in typography. It is commonly used in digital text to represent a question mark symbol with an additional diagonal stroke, resembling a less-than sign (<). This unique combination of symbols can be found in various programming languages and mathematical expressions where it serves as a specific operator or modifier. U+2A7B holds significance in digital communication, particularly in computer science and mathematics, where it may represent various concepts such as an inequality operator in algebra, or a conditional statement in programming languages like Python. Despite its relatively niche usage, the LESS-THAN WITH QUESTION MARK ABOVE character plays an essential role in facilitating precise communication within these specialized fields.

How to type the symbol on Windows

Hold Alt and type 10875 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2A7B. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2A7B to binary: 00101010 01111011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101001 10111011