INTERSECTION WITH OVERBAR·U+2A43

Character Information

Code Point
U+2A43
HEX
2A43
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 A9 83
11100010 10101001 10000011
UTF16 (big Endian)
2A 43
00101010 01000011
UTF16 (little Endian)
43 2A
01000011 00101010
UTF32 (big Endian)
00 00 2A 43
00000000 00000000 00101010 01000011
UTF32 (little Endian)
43 2A 00 00
01000011 00101010 00000000 00000000
HTML Entity
⩃
URI Encoded
%E2%A9%83

Description

The Unicode character U+2A43, known as "INTERSECTION WITH OVERBAR," primarily serves a mathematical purpose in digital text. It is used to represent the set intersection with an overbar in mathematical expressions, denoting the intersection of two or more sets while visually separating them from the surrounding content. This character is particularly useful in set theory and other mathematical disciplines, where it helps to clarify relationships between different elements within a given context. The INTERSECTION WITH OVERBAR character has no notable cultural, linguistic, or technical context beyond its specific role in mathematics, making it a specialized tool for those working with set theory, statistics, and other related fields.

How to type the symbol on Windows

Hold Alt and type 10819 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2A43. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2A43 to binary: 00101010 01000011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101001 10000011