TAI THAM HORA DIGIT EIGHT·U+1A88

Character Information

Code Point
U+1A88
HEX
1A88
Unicode Plane
Basic Multilingual Plane
Category
Decimal Digit Number

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 AA 88
11100001 10101010 10001000
UTF16 (big Endian)
1A 88
00011010 10001000
UTF16 (little Endian)
88 1A
10001000 00011010
UTF32 (big Endian)
00 00 1A 88
00000000 00000000 00011010 10001000
UTF32 (little Endian)
88 1A 00 00
10001000 00011010 00000000 00000000
HTML Entity
᪈
URI Encoded
%E1%AA%88

Description

U+1A88 is the Unicode character code for TAI THAM HORA DIGIT EIGHT, a numeral used in the Tham script of the Horpa language. The Horpa language belongs to the Tai-Kadai language family and is primarily spoken by the Horpa ethnic group, who reside in Southern China, particularly in Yunnan province. In digital text, TAI THAM HORA DIGIT EIGHT serves as a numeral representing the number eight within texts written in this script. The Tham script is an abugida system, where each character represents a consonant with inherent vowel sounds. The use of U+1A88 helps preserve and promote the Horpa language and culture by enabling digital communication in their native script, contributing to linguistic diversity and cultural preservation online.

How to type the symbol on Windows

Hold Alt and type 6792 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1A88. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1A88 to binary: 00011010 10001000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10101010 10001000