TAI THAM HORA DIGIT NINE·U+1A89

Character Information

Code Point
U+1A89
HEX
1A89
Unicode Plane
Basic Multilingual Plane
Category
Decimal Digit Number

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 AA 89
11100001 10101010 10001001
UTF16 (big Endian)
1A 89
00011010 10001001
UTF16 (little Endian)
89 1A
10001001 00011010
UTF32 (big Endian)
00 00 1A 89
00000000 00000000 00011010 10001001
UTF32 (little Endian)
89 1A 00 00
10001001 00011010 00000000 00000000
HTML Entity
᪉
URI Encoded
%E1%AA%89

Description

U+1A89, also known as TAI THAM HORA DIGIT NINE, is a special character in the Unicode standard. This particular character holds a unique position in digital text, serving as a numeral in the Tai Tham script. The Tai Tham script, which belongs to the category of abugida scripts, is primarily used for writing the Lü, Hani, and Va languages spoken by various ethnic groups in China's Yunnan province and Vietnam. The character U+1A89 is crucial in these languages as it represents the number nine, an essential numerical value in all human languages. Its precise usage within digital text aids in the accurate representation of numeric values in contexts such as counting, dates, and measurements within these linguistic domains. Despite being less known globally compared to other numerical symbols, U+1A89 holds great significance for speakers of Tai Tham Hora languages, emphasizing the richness and diversity of written communication across the world.

How to type the symbol on Windows

Hold Alt and type 6793 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1A89. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1A89 to binary: 00011010 10001001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10101010 10001001