PLANCK CONSTANT OVER TWO PI·U+210F

Character Information

Code Point
U+210F
HEX
210F
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 84 8F
11100010 10000100 10001111
UTF16 (big Endian)
21 0F
00100001 00001111
UTF16 (little Endian)
0F 21
00001111 00100001
UTF32 (big Endian)
00 00 21 0F
00000000 00000000 00100001 00001111
UTF32 (little Endian)
0F 21 00 00
00001111 00100001 00000000 00000000
HTML Entity
ℏ
URI Encoded
%E2%84%8F

Description

The Unicode character U+210F, also known as the "Planck Constant over Two Pi" (ℏ/2π), is a symbol primarily used in digital text within scientific and mathematical contexts. It represents the reduced Planck constant divided by two times the constant pi (approximately 3.14159). This character is crucial for expressing precise values in various fields, such as physics, engineering, and computer science, where the ratio of the Planck constant to two times pi often arises in calculations involving angular frequency and quantum mechanics. While this character may not have a significant cultural or linguistic context, its technical importance in accurately conveying these specific mathematical relationships ensures its continued relevance within digital text and scientific literature.

How to type the symbol on Windows

Hold Alt and type 8463 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+210F. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+210F to binary: 00100001 00001111. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10000100 10001111